Look at the following small example: Suppose you have four quiz scores: 1, 3, 5, and 7. The mean is 16 ÷ 4 = 4 points. Subtracting the mean from each number, you get (1 – 4) = –3, (3 – 4) = –1, (5 – 4) = +1, and (7 – 4) = +3. Squaring each of these results, you get 9, 1, 1, and 9. Adding these up, the sum is 20. In this example, n = 4, and therefore n – 1 = 3, so you divide 20 by 3 to get , which is the variance. The units here are “points squared,” which obviously makes no sense. Finally, you take the square root of , to get . The standard deviation for these four quiz scores is points.
where s 1 is the standard deviation of sample 1, s 2 is the standard deviation of sample 2, n 1 is the size of sample 1, n 2 is the size of sample 2, x 1 is the mean of sample 1, x 2 is the mean of sample 2, d is the hypothesized difference between population means, and SE is the standard error.
Hi Dr. Charlz
I am a PG student carrying out a study on Burden and Coping among care givers of stroke survivors. The question I am about to post may seem naive but its quite confusing for me
The objectives are
1. To assess the burden among caregivers of stroke survivors.
2. To identify the coping strategies among caregivers of stroke survivors.
3. To find the association between burden and coping strategies among caregivers of stroke survivors.
4. To find the association between burden and selected demographic variables among caregivers of stroke survivors.
5. To find the association between coping strategies and selected demographic variables among caregivers of stroke survivors.
Statistician recommended to use Chi square for Objective 4, ANOVA for Objective 5 and Independent t-test for Objective 3. I am doubtful on why ANOVA and t-test for the objectives 5 and 3 , I suggested using chi square.
The coping checklist is categorized as Problem focussed,Emotional focussed and Problem and emotional focussed.
Burden is categorized as No burden,Moderate Burden and Severe Burden